Mastering C++: A Comprehensive Quiz Based on 'Thinking in C++'

Disable ads (and more) with a membership for a one time $2.99 payment

Test your C++ skills with our quiz based on Bruce Eckel's 'Thinking in C++'. Dive into object-oriented programming, advanced topics, and fundamentals. Perfect for learners and experts alike. Assess your knowledge and become a C++ master!

Each practice test/flash card set has 50 randomly selected questions from a bank of over 500. You'll get a new set of questions each time!

Practice this question and more.

How does C++ treat the declaration of functions compared to C with regard to type checking?

More leniently
Identically
With stricter type checking
Type checking is optional

The correct answer is: With stricter type checking

C++ treats the declaration of functions with stricter type checking compared to C. This means that in C++, the compiler will be more thorough in checking the types of parameters passed to functions, and will raise errors if there are any mismatches. In contrast, C may allow for more flexibility and leniency in function declarations, potentially leading to more errors or unintended behavior. Option A, "More leniently," is incorrect because the question asks about stricter type checking, not more relaxed. Option B, "Identically," is incorrect because the question specifically states "compared to C." Option D, "Type checking is optional," is incorrect because both C and C++ require type checking for function declarations.