Mastering C++: A Comprehensive Quiz Based on 'Thinking in C++'

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Test your C++ skills with our quiz based on Bruce Eckel's 'Thinking in C++'. Dive into object-oriented programming, advanced topics, and fundamentals. Perfect for learners and experts alike. Assess your knowledge and become a C++ master!

Each practice test/flash card set has 50 randomly selected questions from a bank of over 500. You'll get a new set of questions each time!

Practice this question and more.

In the context of C++, how does using const for aggregates affect the compiler's behavior?

Allows constant folding
Guarantees inlining of aggregate definitions
Forces allocation of storage
Enables compile-time type checking

The correct answer is: Forces allocation of storage

When const is used for aggregates in C++, it forces the compiler to allocate storage for their values at compile-time. This means that the values for the aggregates cannot be changed at runtime, and are essentially treated as constants. Option A, constant folding, refers to the optimization process where the compiler replaces constant expressions with their computed values at compile-time. This is unrelated to the use of const for aggregates. Option B, inlining of aggregate definitions, refers to the compiler inserting the definition of an aggregate directly into its use, rather than creating a separate function call. This is also unrelated to the use of const for aggregates. Option D, compile-time type checking, refers to the compiler verifying the types of expressions and variables at compile-time. While const variables do undergo compile-time type checking, this is not the specific behavior affected by using const for aggregates.